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Popular >

area y=x+6,y=x^3,x=0

Solution

area

y = x + 6, y = x^{3}, x = 0

Solution

10

Solution steps

Apply the area formula:

\int_{0}^{2} x + 6 - x^{3} d x

Solve

\int_{0}^{2} x + 6 - x^{3} d x : 10

The area is:

= 10

Popular Examples

derivative of a^{-x}

\frac{d}{d x} (a^{- x})

d/(dt)(sqrt(3t+1))

\frac{d}{d t} (3 t + 1)

integral of-tln(t)

\int - t ln (t) d t

tangent of x^2,\at x=0 tangent of

x^{2}, at x = 0

(\partial)/(\partial y)(x^3yz^2)

\frac{\partial}{\partial y} (x^{3} y z^{2})

Frequently Asked Questions (FAQ)

What is area y=x+6,y=x^3,x=0 ?
The answer to area y=x+6,y=x^3,x=0 is 10