What is the solution for (dy)/(dx)-(3x^2)/(2y)=0 ?

The solution for (dy)/(dx)-(3x^2)/(2y)=0 is y=sqrt(x^3+c_{1)},y=-sqrt(x^3+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)-(3x^2)/(2y)=0

\frac{d y}{d x} - \frac{3 x ^{2}}{2 y} = 0

y = x^{3} + c_{1}, y = - x^{3} + c_{1}

Solution steps

\frac{d y}{d x} - \frac{3 x ^{2}}{2 y} = 0

Solve separable ODE:

y = x^{3} + c_{1}, y = - x^{3} + c_{1}

y = x^{3} + c_{1}, y = - x^{3} + c_{1}

\frac{d}{d x} (arctan (2 x^{4}))

\int (x^{2} + 3)^{4} 2 x d x

\int e^{- a x^{2}} d x

y = (1 + 4 x)^{11}, (0, 1)

What is the solution for (dy)/(dx)-(3x^2)/(2y)=0 ?
The solution for (dy)/(dx)-(3x^2)/(2y)=0 is y=sqrt(x^3+c_{1)},y=-sqrt(x^3+c_{1)}