What is the tangent of y=(1+4x)^{11},(0,1) ?

The tangent of y=(1+4x)^{11},(0,1) is y=44x+1

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tangent of y=(1+4x)^{11},(0,1)

tangent of

y = (1 + 4 x)^{11}, (0, 1)

y = 44 x + 1

Solution steps

Find the slope of

y = (1 + 4 x)^{11} : \frac{d y}{d x} = 44 (1 + 4 x)^{10}

Compute the slope of

y = (1 + 4 x)^{11}

(0, 1) : m = 44

Find the line with slope m=

44

and passing through

(0, 1) : y = 44 x + 1

y = 44 x + 1

f (x) = \frac{x}{x + 6}, at x = 4

e^{\frac{z}{z - 6}}

\int \frac{16 s - 4}{3 - 2 s + 4 s ^{2}} d s

y = tan (e^{3 t}) + e^{t a n (3 t)}

f (x) = e^{r} + r^{e}

What is the tangent of y=(1+4x)^{11},(0,1) ?
The tangent of y=(1+4x)^{11},(0,1) is y=44x+1