What is the derivative of y=tan(e^{3t})+e^{tan(3t)} ?

The derivative of y=tan(e^{3t})+e^{tan(3t)} is sec^2(e^{3t})e^{3t}*3+e^{tan(3t)}sec^2(3t)*3

What is the first derivative of y=tan(e^{3t})+e^{tan(3t)} ?

The first derivative of y=tan(e^{3t})+e^{tan(3t)} is sec^2(e^{3t})e^{3t}*3+e^{tan(3t)}sec^2(3t)*3

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derivative of

y = tan (e^{3 t}) + e^{t a n (3 t)}

sec^{2} (e^{3 t}) e^{3 t} \cdot 3 + e^{t a n (3 t)} sec^{2} (3 t) \cdot 3

Solution steps

\frac{d}{d t} (tan (e^{3 t}) + e^{t a n (3 t)})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (e^{3 t})) + \frac{d}{d t} (e^{t a n (3 t)})

\frac{d}{d t} (tan (e^{3 t})) = sec^{2} (e^{3 t}) e^{3 t} \cdot 3

\frac{d}{d t} (e^{t a n (3 t)}) = e^{t a n (3 t)} sec^{2} (3 t) \cdot 3

= sec^{2} (e^{3 t}) e^{3 t} \cdot 3 + e^{t a n (3 t)} sec^{2} (3 t) \cdot 3

f (x) = e^{r} + r^{e}

\int \frac{3 x}{x ^{2}} d x

f^{^{'}} (x) = 3 sec (x)

\int_{- 1}^{4} \frac{x}{5 + x} d x

x \to 3 - lim (\frac{∣ x - 3 ∣}{x - 3})

What is the derivative of y=tan(e^{3t})+e^{tan(3t)} ?
The derivative of y=tan(e^{3t})+e^{tan(3t)} is sec^2(e^{3t})e^{3t}*3+e^{tan(3t)}sec^2(3t)*3
What is the first derivative of y=tan(e^{3t})+e^{tan(3t)} ?
The first derivative of y=tan(e^{3t})+e^{tan(3t)} is sec^2(e^{3t})e^{3t}*3+e^{tan(3t)}sec^2(3t)*3