What is the derivative of y=2\sqrt[3]{x} ?

The derivative of y=2\sqrt[3]{x} is 2/(3x^{2/3)}

What is the first derivative of y=2\sqrt[3]{x} ?

The first derivative of y=2\sqrt[3]{x} is 2/(3x^{2/3)}

Popular >

derivative of

\frac{2}{3 x ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 2 \frac{d}{d x} (x^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{1}{3} x^{\frac{1}{3} - 1}

Simplify

2 \cdot \frac{1}{3} x^{\frac{1}{3} - 1} : \frac{2}{3 x ^{\frac{2}{3}}}

= \frac{2}{3 x ^{\frac{2}{3}}}

y = (1 + 4 x)^{11}, (0, 1)

f (x) = \frac{x}{x + 6}, at x = 4

e^{\frac{z}{z - 6}}

\int \frac{16 s - 4}{3 - 2 s + 4 s ^{2}} d s

y = tan (e^{3 t}) + e^{t a n (3 t)}

What is the derivative of y=2\sqrt[3]{x} ?
The derivative of y=2\sqrt[3]{x} is 2/(3x^{2/3)}
What is the first derivative of y=2\sqrt[3]{x} ?
The first derivative of y=2\sqrt[3]{x} is 2/(3x^{2/3)}