What is the general solution for solvefor c,e=r(sec(c/2)-1) ?

The general solution for solvefor c,e=r(sec(c/2)-1) is c=2arcsec(e/r+1)+4pin,c=-2arcsec(e/r+1)+4pin

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solvefor c,e=r(sec(c/2)-1)

solve for

c, e = r (sec (\frac{c}{2}) - 1)

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn, c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

Solution steps

e = r (sec (\frac{c}{2}) - 1)

Switch sides

r (sec (\frac{c}{2}) - 1) = e

Divide both sides by

r; r \neq = 0

sec (\frac{c}{2}) - 1 = \frac{e}{r}; r \neq = 0

Move

1

to the right side

sec (\frac{c}{2}) = \frac{e}{r} + 1; r \neq = 0

Apply trig inverse properties

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn, \frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn

Solve

\frac{c}{2} = arcsec (\frac{e}{r} + 1) + 2 πn : c = 2 arcsec (\frac{e}{r} + 1) + 4 πn

Solve

\frac{c}{2} = - arcsec (\frac{e}{r} + 1) + 2 πn : c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

c = 2 arcsec (\frac{e}{r} + 1) + 4 πn, c = - 2 arcsec (\frac{e}{r} + 1) + 4 πn

arctan (\frac{x}{3}) + arctan (\frac{x}{2}) = arctan (x)

w, y = arctan (1 + 4 w)

cos (8 x) = 1

cos^{4} (a) = 8 cos^{4} (a) - 8 cos^{2} (a) + 1

sin^{2} (a) - 4 sin (a) + 3 = 0

What is the general solution for solvefor c,e=r(sec(c/2)-1) ?
The general solution for solvefor c,e=r(sec(c/2)-1) is c=2arcsec(e/r+1)+4pin,c=-2arcsec(e/r+1)+4pin