What is the general solution for solvefor w,y=arctan(1+4w) ?

The general solution for solvefor w,y=arctan(1+4w) is w=(tan(y))/4-1/4

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solvefor w,y=arctan(1+4w)

solve for

w, y = arctan (1 + 4 w)

w = \frac{tan ( y )}{4} - \frac{1}{4}

Solution steps

y = arctan (1 + 4 w)

Switch sides

arctan (1 + 4 w) = y

Apply trig inverse properties

1 + 4 w = tan (y)

Solve

1 + 4 w = tan (y) : w = \frac{tan ( y )}{4} - \frac{1}{4}

w = \frac{tan ( y )}{4} - \frac{1}{4}

cos (8 x) = 1

cos^{4} (a) = 8 cos^{4} (a) - 8 cos^{2} (a) + 1

sin^{2} (a) - 4 sin (a) + 3 = 0

4 sin^{2} (x) - 4 cos (x) - 1 = 0

3 cos^{2} (x) + 2 cos (x) - 8 = 0

What is the general solution for solvefor w,y=arctan(1+4w) ?
The general solution for solvefor w,y=arctan(1+4w) is w=(tan(y))/4-1/4