What is the general solution for sin^2(a)-4sin(a)+3=0 ?

The general solution for sin^2(a)-4sin(a)+3=0 is a= pi/2+2pin

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sin^2(a)-4sin(a)+3=0

sin^{2} (a) - 4 sin (a) + 3 = 0

a = \frac{π}{2} + 2 πn

Solution steps

sin^{2} (a) - 4 sin (a) + 3 = 0

Solve by substitution

sin (a) = 3, sin (a) = 1

sin (a) = 3 :

No Solution

sin (a) = 1 : a = \frac{π}{2} + 2 πn

Combine all the solutions

a = \frac{π}{2} + 2 πn

4 sin^{2} (x) - 4 cos (x) - 1 = 0

3 cos^{2} (x) + 2 cos (x) - 8 = 0

tan (a) + sec (a) = \frac{3}{2}

3 cos^{2} (x) + 4 cos^{4} (x) - 5 = 0

cos (2 x + 3) = 0

What is the general solution for sin^2(a)-4sin(a)+3=0 ?
The general solution for sin^2(a)-4sin(a)+3=0 is a= pi/2+2pin