What is the general solution for tan(x^2)+1=0 ?

The general solution for tan(x^2)+1=0 is x=(sqrt(3pi+4pin))/2 ,x=-(sqrt(3pi+4pin))/2

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tan(x^2)+1=0

tan (x^{2}) + 1 = 0

x = \frac{3 π + 4 πn}{2}, x = - \frac{3 π + 4 πn}{2}

Solution steps

tan (x^{2}) + 1 = 0

Move

1

to the right side

tan (x^{2}) = - 1

General solutions for

tan (x^{2}) = - 1

x^{2} = \frac{3 π}{4} + πn

Solve

x^{2} = \frac{3 π}{4} + πn : x = \frac{3 π + 4 πn}{2}, x = - \frac{3 π + 4 πn}{2}

x = \frac{3 π + 4 πn}{2}, x = - \frac{3 π + 4 πn}{2}

\frac{( 1 + cos ^{2} ( a ) )}{sin ^{2} ( a )} = \frac{5}{3}

d^{2} + 13 d + 36 = \frac{sin ^{2} ( x )}{2}

\frac{tan ^{2} ( x ) - 4}{cos ( x ) + 5} = 0

cot^{2} (x) = sec^{2} (x) - 1

\frac{cos ^{2} ( a ) - 1}{sin ^{2} ( a ) + 1} = 0

What is the general solution for tan(x^2)+1=0 ?
The general solution for tan(x^2)+1=0 is x=(sqrt(3pi+4pin))/2 ,x=-(sqrt(3pi+4pin))/2