What is the general solution for (cos^2(a)-1)/(sin^2(a)+1)=0 ?

The general solution for (cos^2(a)-1)/(sin^2(a)+1)=0 is a=2pin,a=pi+2pin

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(cos^2(a)-1)/(sin^2(a)+1)=0

\frac{cos ^{2} ( a ) - 1}{sin ^{2} ( a ) + 1} = 0

a = 2 πn, a = π + 2 πn

Solution steps

\frac{cos ^{2} ( a ) - 1}{sin ^{2} ( a ) + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos^{2} (a) - 1 = 0

Solve by substitution

cos (a) = 1, cos (a) = - 1

cos (a) = 1 : a = 2 πn

cos (a) = - 1 : a = π + 2 πn

Combine all the solutions

a = 2 πn, a = π + 2 πn

7 sin^{2} (x) + 2 sin^{2} (x) - 3 cos^{2} (x) = 0

sin^{2} (x) - cos^{2} (x) = cos^{4} (x)

sin^{2} (x) + 2 cos^{2} (x) = 1

\frac{sin ^{2} ( a ) + 1}{tan ^{2} ( a )} = 1

2 cos^{2} (x) = - 3 sin (x) cos (x)

What is the general solution for (cos^2(a)-1)/(sin^2(a)+1)=0 ?
The general solution for (cos^2(a)-1)/(sin^2(a)+1)=0 is a=2pin,a=pi+2pin