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Popular >

(tan^2(b)+1)/((tan(x)))=csc^2(b)

Solution

\frac{tan ^{2} ( b ) + 1}{( tan ( x ) )} = csc^{2} (b)

Solution

x = arctan (\frac{tan ^{2} ( b ) + 1}{csc ^{2} ( b )}) + πn

Solution steps

\frac{tan ^{2} ( b ) + 1}{( tan ( x ) )} = csc^{2} (b)

Multiply both sides by

tan (x)

tan^{2} (b) + 1 = csc^{2} (b) tan (x)

Switch sides

csc^{2} (b) tan (x) = tan^{2} (b) + 1

Divide both sides by

csc^{2} (b)

tan (x) = \frac{tan ^{2} ( b ) + 1}{csc ^{2} ( b )}

Apply trig inverse properties

x = arctan (\frac{tan ^{2} ( b ) + 1}{csc ^{2} ( b )}) + πn

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Frequently Asked Questions (FAQ)

What is the general solution for (tan^2(b)+1)/((tan(x)))=csc^2(b) ?
The general solution for (tan^2(b)+1)/((tan(x)))=csc^2(b) is x=arctan((tan^2(b)+1)/(csc^2(b)))+pin