What is the general solution for sin(a)+sin(120+a)+sin(120-a)=0 ?

The general solution for sin(a)+sin(120+a)+sin(120-a)=0 is a=120+180n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(a)+sin(120+a)+sin(120-a)=0

sin (a) + sin (12 0^{\circ} + a) + sin (12 0^{\circ} - a) = 0

a = 12 0^{\circ} + 18 0^{\circ} n

Solution steps

sin (a) + sin (12 0^{\circ} + a) + sin (12 0^{\circ} - a) = 0

Rewrite using trig identities

tan (a) + 3 = 0

Move

3

to the right side

tan (a) = - 3

General solutions for

tan (a) = - 3

a = 12 0^{\circ} + 18 0^{\circ} n

3 sin (x) sin (x) = 5 cos (x) - 2

\frac{cos ( x ) + 3 cos ( x )}{2 + 2} = 0

3 tan^{3} (x) - tan^{2} (x) - tan (x) - 1 = 0

cos (2 x + 60) = cos (x)

3 tan (x) - 3 cot (x) - 1 = 0

What is the general solution for sin(a)+sin(120+a)+sin(120-a)=0 ?
The general solution for sin(a)+sin(120+a)+sin(120-a)=0 is a=120+180n