What is the general solution for 3sqrt(cot(x-10))=4 ?

The general solution for 3sqrt(cot(x-10))=4 is x=0.51238…+180n+10

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3sqrt(cot(x-10))=4

3 cot (x - 1 0^{\circ}) = 4

x = 0.51238 \dots + 18 0^{\circ} n + 1 0^{\circ}

Solution steps

3 cot (x - 1 0^{\circ}) = 4

Divide both sides by

3

cot (x - 1 0^{\circ}) = \frac{4}{3}

Square both sides:

cot (x - 1 0^{\circ}) = \frac{16}{9}

cot (x - 1 0^{\circ}) = \frac{16}{9}

Verify Solutions:

cot (x - 1 0^{\circ}) = \frac{16}{9}

True

The solution is

cot (x - 1 0^{\circ}) = \frac{16}{9}

Apply trig inverse properties

x - 1 0^{\circ} = arccot (\frac{16}{9}) + 18 0^{\circ} n

Solve

x - 1 0^{\circ} = arccot (\frac{16}{9}) + 18 0^{\circ} n : x = arccot (\frac{16}{9}) + 18 0^{\circ} n + 1 0^{\circ}

x = arccot (\frac{16}{9}) + 18 0^{\circ} n + 1 0^{\circ}

Show solutions in decimal form

x = 0.51238 \dots + 18 0^{\circ} n + 1 0^{\circ}

2.4638 cos (x) = 2.5843

tan^{2} (x) = 2 tan (x) + 2 tan^{3} (x)

t, cos (wt + k) = \frac{20}{( 2 \cdot π \cdot f ) ^{2}}

0 = - cos (x) (2 sin (x) + 3)

28 cos (t) = 20, 0^{\circ} \leq t < 36 0^{\circ}

What is the general solution for 3sqrt(cot(x-10))=4 ?
The general solution for 3sqrt(cot(x-10))=4 is x=0.51238…+180n+10