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Popular Trigonometry >

solvefor t,cos(wt+k)=(20)/((2*pi*f)^2)

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Solution

solvefor

Solution

t=warccos(π2f25​)​+w2πn​−wk​,t=−warccos(π2f25​)​+w2πn​−wk​
+1
Radians
t=warccos(π2f25​)​−wk​+w2π​n,t=−warccos(π2f25​)​−wk​+w2π​n
Solution steps
cos(wt+k)=(2πf)220​
Simplify (2πf)220​:π2f25​
(2πf)220​
(2πf)2=22π2f2
(2πf)2
Apply exponent rule: (a⋅b)n=anbn=22π2f2
=22π2f220​
Factor 20:22⋅5
Factor 20=22⋅5
=22π2f222⋅5​
Cancel the common factor: 22=π2f25​
Apply trig inverse properties
cos(wt+k)=π2f25​
General solutions for cos(wt+k)=π2f25​cos(x)=a⇒x=arccos(a)+2πn,x=−arccos(a)+2πnwt+k=arccos(π2f25​)+2πn,wt+k=−arccos(π2f25​)+2πn
wt+k=arccos(π2f25​)+2πn,wt+k=−arccos(π2f25​)+2πn
Solve wt+k=arccos(π2f25​)+2πn:t=warccos(π2f25​)​+w2πn​−wk​;w=0
wt+k=arccos(π2f25​)+2πn
Move kto the right side
wt+k=arccos(π2f25​)+2πn
Subtract k from both sideswt+k−k=arccos(π2f25​)+2πn−k
Simplifywt=arccos(π2f25​)+2πn−k
wt=arccos(π2f25​)+2πn−k
Divide both sides by w;w=0
wt=arccos(π2f25​)+2πn−k
Divide both sides by w;w=0wwt​=warccos(π2f25​)​+w2πn​−wk​;w=0
Simplifyt=warccos(π2f25​)​+w2πn​−wk​;w=0
t=warccos(π2f25​)​+w2πn​−wk​;w=0
Solve wt+k=−arccos(π2f25​)+2πn:t=−warccos(π2f25​)​+w2πn​−wk​;w=0
wt+k=−arccos(π2f25​)+2πn
Move kto the right side
wt+k=−arccos(π2f25​)+2πn
Subtract k from both sideswt+k−k=−arccos(π2f25​)+2πn−k
Simplifywt=−arccos(π2f25​)+2πn−k
wt=−arccos(π2f25​)+2πn−k
Divide both sides by w;w=0
wt=−arccos(π2f25​)+2πn−k
Divide both sides by w;w=0wwt​=−warccos(π2f25​)​+w2πn​−wk​;w=0
Simplifyt=−warccos(π2f25​)​+w2πn​−wk​;w=0
t=−warccos(π2f25​)​+w2πn​−wk​;w=0
t=warccos(π2f25​)​+w2πn​−wk​,t=−warccos(π2f25​)​+w2πn​−wk​

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