What is the general solution for 0=-cos(x)(2sin(x)+3) ?

The general solution for 0=-cos(x)(2sin(x)+3) is x= pi/2+2pin,x=(3pi)/2+2pin

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0=-cos(x)(2sin(x)+3)

0 = - cos (x) (2 sin (x) + 3)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

0 = - cos (x) (2 sin (x) + 3)

Switch sides

- cos (x) (2 sin (x) + 3) = 0

Solving each part separately

cos (x) = 0 or 2 sin (x) + 3 = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

2 sin (x) + 3 = 0 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

28 cos (t) = 20, 0^{\circ} \leq t < 36 0^{\circ}

8 tan (\frac{x}{2}) + 8 cos (x) tan (\frac{x}{2}) = 1

sin (a) = 0.5937

tan (x) = \frac{18}{25}

sin^{2} (x) = \frac{3}{2}

What is the general solution for 0=-cos(x)(2sin(x)+3) ?
The general solution for 0=-cos(x)(2sin(x)+3) is x= pi/2+2pin,x=(3pi)/2+2pin