What is the general solution for sin(3x-pi/4)=(sqrt(2))/2 ?

The general solution for sin(3x-pi/4)=(sqrt(2))/2 is x= pi/6+(2pin)/3 ,x=(2pin)/3+pi/3

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sin(3x-pi/4)=(sqrt(2))/2

sin (3 x - \frac{π}{4}) = \frac{2}{2}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{2 πn}{3} + \frac{π}{3}

Solution steps

sin (3 x - \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (3 x - \frac{π}{4}) = \frac{2}{2}

3 x - \frac{π}{4} = \frac{π}{4} + 2 πn, 3 x - \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

3 x - \frac{π}{4} = \frac{π}{4} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 x - \frac{π}{4} = \frac{3 π}{4} + 2 πn : x = \frac{2 πn}{3} + \frac{π}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{2 πn}{3} + \frac{π}{3}

sin (2 θ) = \frac{- 3}{4}, \frac{3 π}{2} \leq 2 θ \leq 2 π

3 cot (x - 1 0^{\circ}) = 4

2.4638 cos (x) = 2.5843

tan^{2} (x) = 2 tan (x) + 2 tan^{3} (x)

t, cos (wt + k) = \frac{20}{( 2 \cdot π \cdot f ) ^{2}}

What is the general solution for sin(3x-pi/4)=(sqrt(2))/2 ?
The general solution for sin(3x-pi/4)=(sqrt(2))/2 is x= pi/6+(2pin)/3 ,x=(2pin)/3+pi/3