What is the general solution for -sin(x)+2cos(x)=0 ?

The general solution for -sin(x)+2cos(x)=0 is x=1.10714…+pin

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-sin(x)+2cos(x)=0

- sin (x) + 2 cos (x) = 0

x = 1.10714 \dots + πn

Solution steps

- sin (x) + 2 cos (x) = 0

Rewrite using trig identities

- tan (x) + 2 = 0

Move

2

to the right side

- tan (x) = - 2

Divide both sides by

- 1

tan (x) = 2

Apply trig inverse properties

x = arctan (2) + πn

Show solutions in decimal form

x = 1.10714 \dots + πn

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

(cosh (x)) = sinh (x)

- 6 tan^{2} (θ) + 4 tan (θ) = - tan (θ) + 1

8 cos^{2} (x) + 14 cos (x) + 3 = 0

0 = 4 cos (x) sin (x) - sin (x)

What is the general solution for -sin(x)+2cos(x)=0 ?
The general solution for -sin(x)+2cos(x)=0 is x=1.10714…+pin