What is the general solution for (sin(θ))/(140)=(sin(110))/(622) ?

The general solution for (sin(θ))/(140)=(sin(110))/(622) is θ=0.21311…+360n,θ=180-0.21311…+360n

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(sin(θ))/(140)=(sin(110))/(622)

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

θ = 0.21311 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.21311 \dots + 36 0^{\circ} n

Solution steps

\frac{sin ( θ )}{140} = \frac{sin ( 11 0 ^{\circ} )}{622}

Multiply both sides by

10

\frac{sin ( θ )}{14} = \frac{5 sin ( 11 0 ^{\circ} )}{311}

Multiply both sides by

14

sin (θ) = \frac{70 sin ( 11 0 ^{\circ} )}{311}

Apply trig inverse properties

θ = arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{70 sin ( 11 0 ^{\circ} )}{311}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.21311 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.21311 \dots + 36 0^{\circ} n

(cosh (x)) = sinh (x)

- 6 tan^{2} (θ) + 4 tan (θ) = - tan (θ) + 1

8 cos^{2} (x) + 14 cos (x) + 3 = 0

0 = 4 cos (x) sin (x) - sin (x)

sin (x) cos (x) = tan (x)

What is the general solution for (sin(θ))/(140)=(sin(110))/(622) ?
The general solution for (sin(θ))/(140)=(sin(110))/(622) is θ=0.21311…+360n,θ=180-0.21311…+360n