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(8cos(x)-4)(sin(x))=0,0<= x<2pi

Solution

(8 cos (x) - 4) (sin (x)) = 0, 0 \leq x < 2 π

Solution

x = \frac{π}{3}, x = \frac{5 π}{3}, x = 0, x = π

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Solution steps

(8 cos (x) - 4) (sin (x)) = 0, 0 \leq x < 2 π

Solving each part separately

8 cos (x) - 4 = 0 or sin (x) = 0

8 cos (x) - 4 = 0, 0 \leq x < 2 π : x = \frac{π}{3}, x = \frac{5 π}{3}

sin (x) = 0, 0 \leq x < 2 π : x = 0, x = π

Combine all the solutions

x = \frac{π}{3}, x = \frac{5 π}{3}, x = 0, x = π

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Frequently Asked Questions (FAQ)

What is the general solution for (8cos(x)-4)(sin(x))=0,0<= x<2pi ?
The general solution for (8cos(x)-4)(sin(x))=0,0<= x<2pi is x= pi/3 ,x=(5pi)/3 ,x=0,x=pi