What is the general solution for 3cos(2x)=1 ?

The general solution for 3cos(2x)=1 is x=(1.23095…)/2+pin,x=pi-(1.23095…)/2+pin

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3cos(2x)=1

3 cos (2 x) = 1

x = \frac{1.23095 \dots}{2} + πn, x = π - \frac{1.23095 \dots}{2} + πn

Solution steps

3 cos (2 x) = 1

Divide both sides by

3

cos (2 x) = \frac{1}{3}

Apply trig inverse properties

2 x = arccos (\frac{1}{3}) + 2 πn, 2 x = 2 π - arccos (\frac{1}{3}) + 2 πn

Solve

2 x = arccos (\frac{1}{3}) + 2 πn : x = \frac{arccos ( \frac{1}{3} )}{2} + πn

Solve

2 x = 2 π - arccos (\frac{1}{3}) + 2 πn : x = π - \frac{arccos ( \frac{1}{3} )}{2} + πn

x = \frac{arccos ( \frac{1}{3} )}{2} + πn, x = π - \frac{arccos ( \frac{1}{3} )}{2} + πn

Show solutions in decimal form

x = \frac{1.23095 \dots}{2} + πn, x = π - \frac{1.23095 \dots}{2} + πn

cos^{2} (x) = (1 + sin (x)) (1 - cos (x))

tan (x) = 1, - π < x \leq π

\frac{1}{2 cos ^{2} ( x - 1 )} = \frac{1 + tan ^{2} ( x )}{2 sec ^{2} ( x )}

sin (2 x) - 2 cos (2 x) = 0

tan (x) = \frac{87.092}{86.676}

What is the general solution for 3cos(2x)=1 ?
The general solution for 3cos(2x)=1 is x=(1.23095…)/2+pin,x=pi-(1.23095…)/2+pin