What is the general solution for cos(x)*cos(35)=1-sin(x)*sin(35) ?

The general solution for cos(x)*cos(35)=1-sin(x)*sin(35) is x=-360n+35

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(x)cos(35)=1-sin(x)sin(35)

cos (x) \cdot cos (3 5^{\circ}) = 1 - sin (x) \cdot sin (3 5^{\circ})

x = - 36 0^{\circ} n + 3 5^{\circ}

Solution steps

cos (x) cos (3 5^{\circ}) = 1 - sin (x) sin (3 5^{\circ})

Subtract

1 - sin (x) sin (3 5^{\circ})

from both sides

cos (3 5^{\circ}) cos (x) - 1 + sin (3 5^{\circ}) sin (x) = 0

Rewrite using trig identities

- 1 + cos (3 5^{\circ} - x) = 0

Move

1

to the right side

cos (3 5^{\circ} - x) = 1

General solutions for

cos (3 5^{\circ} - x) = 1

3 5^{\circ} - x = 0 + 36 0^{\circ} n

Solve

3 5^{\circ} - x = 0 + 36 0^{\circ} n : x = - 36 0^{\circ} n + 3 5^{\circ}

x = - 36 0^{\circ} n + 3 5^{\circ}

sin (3 θ - 15) = 0.7

tan (x - \frac{π}{6}) = 1

cos^{2} (x) + (\frac{1 - 2}{2}) cos (x) - \frac{2}{4} = 0

tan^{2} (\frac{x}{2}) = - 2

sin^{2} (θ) - 1 = 2 sin (θ)

What is the general solution for cos(x)*cos(35)=1-sin(x)*sin(35) ?
The general solution for cos(x)*cos(35)=1-sin(x)*sin(35) is x=-360n+35