What is the general solution for sin^2(θ)-1=2sin(θ) ?

The general solution for sin^2(θ)-1=2sin(θ) is θ=-0.42707…+2pin,θ=pi+0.42707…+2pin

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sin^2(θ)-1=2sin(θ)

sin^{2} (θ) - 1 = 2 sin (θ)

θ = - 0.42707 \dots + 2 πn, θ = π + 0.42707 \dots + 2 πn

Solution steps

sin^{2} (θ) - 1 = 2 sin (θ)

Solve by substitution

sin (θ) = 1 + 2, sin (θ) = 1 - 2

sin (θ) = 1 + 2 :

No Solution

sin (θ) = 1 - 2 : θ = arcsin (1 - 2) + 2 πn, θ = π + arcsin (- 1 + 2) + 2 πn

Combine all the solutions

θ = arcsin (1 - 2) + 2 πn, θ = π + arcsin (- 1 + 2) + 2 πn

Show solutions in decimal form

θ = - 0.42707 \dots + 2 πn, θ = π + 0.42707 \dots + 2 πn

- 3 sin^{2} (x) + 2 = 0

16 sin (3 x) cos (x) + 83 sin (3 x) - 2 cos (x) - 3 = 0

tan (C) = 2.56

cos (3 y) = 0

tan (x) = \frac{0.33}{0.44}

What is the general solution for sin^2(θ)-1=2sin(θ) ?
The general solution for sin^2(θ)-1=2sin(θ) is θ=-0.42707…+2pin,θ=pi+0.42707…+2pin