解答
16sin(3x)cos(x)+83sin(3x)−2cos(x)−3=0
解答
x=30.12532…+32πn,x=3π−30.12532…+32πn,x=65π+2πn,x=67π+2πn
+1
度数
x=2.39358…∘+120∘n,x=57.60641…∘+120∘n,x=150∘+360∘n,x=210∘+360∘n求解步骤
16sin(3x)cos(x)+83sin(3x)−2cos(x)−3=0
分解 16sin(3x)cos(x)+83sin(3x)−2cos(x)−3:(−1+8sin(3x))(2cos(x)+3)
16sin(3x)cos(x)+83sin(3x)−2cos(x)−3
分解 16sin(3x)cos(x)−2cos(x):2cos(x)(8sin(3x)−1)
16sin(3x)cos(x)−2cos(x)
改写为=8⋅2cos(x)sin(3x)−1⋅2cos(x)
因式分解出通项 2cos(x)=2cos(x)(8sin(3x)−1)
分解 83sin(3x)−3:3(8sin(3x)−1)
83sin(3x)−3
因式分解出通项 3=3(8sin(3x)−1)
=2cos(x)(8sin(3x)−1)+3(8sin(3x)−1)
因式分解出通项 (−1+8sin(3x))=(−1+8sin(3x))(2cos(x)+3)
(−1+8sin(3x))(2cos(x)+3)=0
分别求解每个部分−1+8sin(3x)=0or2cos(x)+3=0
−1+8sin(3x)=0:x=3arcsin(81)+32πn,x=3π−3arcsin(81)+32πn
−1+8sin(3x)=0
将 1到右边
−1+8sin(3x)=0
两边加上 1−1+8sin(3x)+1=0+1
化简8sin(3x)=1
8sin(3x)=1
两边除以 8
8sin(3x)=1
两边除以 888sin(3x)=81
化简sin(3x)=81
sin(3x)=81
使用反三角函数性质
sin(3x)=81
sin(3x)=81的通解sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πn3x=arcsin(81)+2πn,3x=π−arcsin(81)+2πn
3x=arcsin(81)+2πn,3x=π−arcsin(81)+2πn
解 3x=arcsin(81)+2πn:x=3arcsin(81)+32πn
3x=arcsin(81)+2πn
两边除以 3
3x=arcsin(81)+2πn
两边除以 333x=3arcsin(81)+32πn
化简x=3arcsin(81)+32πn
x=3arcsin(81)+32πn
解 3x=π−arcsin(81)+2πn:x=3π−3arcsin(81)+32πn
3x=π−arcsin(81)+2πn
两边除以 3
3x=π−arcsin(81)+2πn
两边除以 333x=3π−3arcsin(81)+32πn
化简x=3π−3arcsin(81)+32πn
x=3π−3arcsin(81)+32πn
x=3arcsin(81)+32πn,x=3π−3arcsin(81)+32πn
2cos(x)+3=0:x=65π+2πn,x=67π+2πn
2cos(x)+3=0
将 3到右边
2cos(x)+3=0
两边减去 32cos(x)+3−3=0−3
化简2cos(x)=−3
2cos(x)=−3
两边除以 2
2cos(x)=−3
两边除以 222cos(x)=2−3
化简cos(x)=−23
cos(x)=−23
cos(x)=−23的通解
cos(x) 周期表(周期为 2πn):
x06π4π3π2π32π43π65πcos(x)12322210−21−22−23xπ67π45π34π23π35π47π611πcos(x)−1−23−22−210212223
x=65π+2πn,x=67π+2πn
x=65π+2πn,x=67π+2πn
合并所有解x=3arcsin(81)+32πn,x=3π−3arcsin(81)+32πn,x=65π+2πn,x=67π+2πn
以小数形式表示解x=30.12532…+32πn,x=3π−30.12532…+32πn,x=65π+2πn,x=67π+2πn