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Popular Trigonometry >

5=sinh(x)

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Solution

5=sinh(x)

Solution

x=ln(5+26​)
+1
Degrees
x=132.49295…∘
Solution steps
5=sinh(x)
Switch sidessinh(x)=5
Rewrite using trig identities
sinh(x)=5
Use the Hyperbolic identity: sinh(x)=2ex−e−x​2ex−e−x​=5
2ex−e−x​=5
2ex−e−x​=5:x=ln(5+26​)
2ex−e−x​=5
Multiply both sides by 22ex−e−x​⋅2=5⋅2
Simplifyex−e−x=10
Apply exponent rules
ex−e−x=10
Apply exponent rule: abc=(ab)ce−x=(ex)−1ex−(ex)−1=10
ex−(ex)−1=10
Rewrite the equation with ex=uu−(u)−1=10
Solve u−u−1=10:u=5+26​,u=5−26​
u−u−1=10
Refineu−u1​=10
Multiply both sides by u
u−u1​=10
Multiply both sides by uuu−u1​u=10u
Simplify
uu−u1​u=10u
Simplify uu:u2
uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=u1+1
Add the numbers: 1+1=2=u2
Simplify −u1​u:−1
−u1​u
Multiply fractions: a⋅cb​=ca⋅b​=−u1⋅u​
Cancel the common factor: u=−1
u2−1=10u
u2−1=10u
u2−1=10u
Solve u2−1=10u:u=5+26​,u=5−26​
u2−1=10u
Move 10uto the left side
u2−1=10u
Subtract 10u from both sidesu2−1−10u=10u−10u
Simplifyu2−1−10u=0
u2−1−10u=0
Write in the standard form ax2+bx+c=0u2−10u−1=0
Solve with the quadratic formula
u2−10u−1=0
Quadratic Equation Formula:
For a=1,b=−10,c=−1u1,2​=2⋅1−(−10)±(−10)2−4⋅1⋅(−1)​​
u1,2​=2⋅1−(−10)±(−10)2−4⋅1⋅(−1)​​
(−10)2−4⋅1⋅(−1)​=226​
(−10)2−4⋅1⋅(−1)​
Apply rule −(−a)=a=(−10)2+4⋅1⋅1​
Apply exponent rule: (−a)n=an,if n is even(−10)2=102=102+4⋅1⋅1​
Multiply the numbers: 4⋅1⋅1=4=102+4​
102=100=100+4​
Add the numbers: 100+4=104=104​
Prime factorization of 104:23⋅13
104
104divides by 2104=52⋅2=2⋅52
52divides by 252=26⋅2=2⋅2⋅26
26divides by 226=13⋅2=2⋅2⋅2⋅13
2,13 are all prime numbers, therefore no further factorization is possible=2⋅2⋅2⋅13
=23⋅13
=23⋅13​
Apply exponent rule: ab+c=ab⋅ac=22⋅2⋅13​
Apply radical rule: =22​2⋅13​
Apply radical rule: 22​=2=22⋅13​
Refine=226​
u1,2​=2⋅1−(−10)±226​​
Separate the solutionsu1​=2⋅1−(−10)+226​​,u2​=2⋅1−(−10)−226​​
u=2⋅1−(−10)+226​​:5+26​
2⋅1−(−10)+226​​
Apply rule −(−a)=a=2⋅110+226​​
Multiply the numbers: 2⋅1=2=210+226​​
Factor 10+226​:2(5+26​)
10+226​
Rewrite as=2⋅5+226​
Factor out common term 2=2(5+26​)
=22(5+26​)​
Divide the numbers: 22​=1=5+26​
u=2⋅1−(−10)−226​​:5−26​
2⋅1−(−10)−226​​
Apply rule −(−a)=a=2⋅110−226​​
Multiply the numbers: 2⋅1=2=210−226​​
Factor 10−226​:2(5−26​)
10−226​
Rewrite as=2⋅5−226​
Factor out common term 2=2(5−26​)
=22(5−26​)​
Divide the numbers: 22​=1=5−26​
The solutions to the quadratic equation are:u=5+26​,u=5−26​
u=5+26​,u=5−26​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of u−u−1 and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=5+26​,u=5−26​
u=5+26​,u=5−26​
Substitute back u=ex,solve for x
Solve ex=5+26​:x=ln(5+26​)
ex=5+26​
Apply exponent rules
ex=5+26​
If f(x)=g(x), then ln(f(x))=ln(g(x))ln(ex)=ln(5+26​)
Apply log rule: ln(ea)=aln(ex)=xx=ln(5+26​)
x=ln(5+26​)
Solve ex=5−26​:No Solution for x∈R
ex=5−26​
af(x) cannot be zero or negative for x∈RNoSolutionforx∈R
x=ln(5+26​)
x=ln(5+26​)

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Frequently Asked Questions (FAQ)

  • What is the general solution for 5=sinh(x) ?

    The general solution for 5=sinh(x) is x=ln(5+sqrt(26))
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