What is the general solution for 6sqrt(2)+12cos(x-45)=0 ?

The general solution for 6sqrt(2)+12cos(x-45)=0 is x=360n+180,x=360n+270

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6sqrt(2)+12cos(x-45)=0

62 + 12 cos (x - 4 5^{\circ}) = 0

x = 36 0^{\circ} n + 18 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}

Solution steps

62 + 12 cos (x - 4 5^{\circ}) = 0

Move

62

to the right side

12 cos (x - 4 5^{\circ}) = - 62

Divide both sides by

12

cos (x - 4 5^{\circ}) = - \frac{2}{2}

General solutions for

cos (x - 4 5^{\circ}) = - \frac{2}{2}

x - 4 5^{\circ} = 13 5^{\circ} + 36 0^{\circ} n, x - 4 5^{\circ} = 22 5^{\circ} + 36 0^{\circ} n

Solve

x - 4 5^{\circ} = 13 5^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 18 0^{\circ}

Solve

x - 4 5^{\circ} = 22 5^{\circ} + 36 0^{\circ} n : x = 36 0^{\circ} n + 27 0^{\circ}

x = 36 0^{\circ} n + 18 0^{\circ}, x = 36 0^{\circ} n + 27 0^{\circ}

(2 \cdot 9.8 \cdot l (1 - cos (θ))) = 0.018

\frac{1}{tan ( x )} = 0.5

tan (θ) = - \frac{16.54}{34.01}

sin (\frac{x}{7}) = \frac{3 ^{\frac{1}{2}}}{2}, π < x < 3 π

2 sec^{2} (x) - 13 sec (x) + 20 = 0, 2 π \leq x \leq 4 π

What is the general solution for 6sqrt(2)+12cos(x-45)=0 ?
The general solution for 6sqrt(2)+12cos(x-45)=0 is x=360n+180,x=360n+270