What is the general solution for -16cos(2x)=0 ?

The general solution for -16cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin

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-16cos(2x)=0

- 16 cos (2 x) = 0

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

- 16 cos (2 x) = 0

Divide both sides by

- 16

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

62 + 12 cos (x - 4 5^{\circ}) = 0

(2 \cdot 9.8 \cdot l (1 - cos (θ))) = 0.018

\frac{1}{tan ( x )} = 0.5

tan (θ) = - \frac{16.54}{34.01}

sin (\frac{x}{7}) = \frac{3 ^{\frac{1}{2}}}{2}, π < x < 3 π

What is the general solution for -16cos(2x)=0 ?
The general solution for -16cos(2x)=0 is x= pi/4+pin,x=(3pi)/4+pin