What is the general solution for sqrt(-9cos(θ))=(3sqrt(2))/2 ?

The general solution for sqrt(-9cos(θ))=(3sqrt(2))/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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sqrt(-9cos(θ))=(3sqrt(2))/2

- 9 cos (θ) = \frac{3 2}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

- 9 cos (θ) = \frac{3 2}{2}

Square both sides:

- 9 cos (θ) = \frac{9}{2}

- 9 cos (θ) = \frac{9}{2}

Solve

- 9 cos (θ) = \frac{9}{2} : cos (θ) = - \frac{1}{2}

cos (θ) = - \frac{1}{2}

Verify Solutions:

cos (θ) = - \frac{1}{2}

True

The solution is

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sec (a) = 1 + tan (a)

arctan (θ) = \frac{2}{2 3}

3 sin (x) = + sin (x)

x, (D^{2} - 3 D + 2) y = sec^{2} (e^{- x})

sin (θ) = \frac{7 sin ( 14 0 ^{\circ} )}{16.12288984}

What is the general solution for sqrt(-9cos(θ))=(3sqrt(2))/2 ?
The general solution for sqrt(-9cos(θ))=(3sqrt(2))/2 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin