What is the general solution for tan^2(θ)-tan(θ)=0,θ,0<= θ<2pi ?

The general solution for tan^2(θ)-tan(θ)=0,θ,0<= θ<2pi is No Solution for θ\in\mathbb{R}

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tan^2(θ)-tan(θ)=0,θ,0<= θ<2pi

tan^{2} (θ) - tan (θ) = 0, θ, 0 \leq θ < 2 π

No Solution for θ \in R

Solution steps

tan^{2} (θ) - tan (θ) = 0, θ, 0 \leq θ < 2 π

Solve by substitution

tan (θ) = 1, tan (θ) = 0

tan (θ) = 1, θ :

No Solution

tan (θ) = 0, θ :

No Solution

Combine all the solutions

No Solution for θ \in R

cos (4 x) - 4 cos (2 x) = 5

sin (x) = sin (x + (- 3) π)

sin (2 x) - \frac{2}{3} = 0

2 sin (θ) + cos (2 θ) = 0

sin (x + \frac{π}{4}) = 2 cos (x + \frac{π}{4})

What is the general solution for tan^2(θ)-tan(θ)=0,θ,0<= θ<2pi ?
The general solution for tan^2(θ)-tan(θ)=0,θ,0<= θ<2pi is No Solution for θ\in\mathbb{R}