What is the general solution for cos(A-25)+cos(A+25)=cos(25) ?

The general solution for cos(A-25)+cos(A+25)=cos(25) is A=60+360n,A=300+360n

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cos(A-25)+cos(A+25)=cos(25)

cos (A - 2 5^{\circ}) + cos (A + 2 5^{\circ}) = cos (2 5^{\circ})

A = 6 0^{\circ} + 36 0^{\circ} n, A = 30 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (A - 2 5^{\circ}) + cos (A + 2 5^{\circ}) = cos (2 5^{\circ})

Rewrite using trig identities

2 cos (2 5^{\circ}) cos (A) = cos (2 5^{\circ})

Divide both sides by

2 cos (2 5^{\circ})

cos (A) = \frac{1}{2}

General solutions for

cos (A) = \frac{1}{2}

A = 6 0^{\circ} + 36 0^{\circ} n, A = 30 0^{\circ} + 36 0^{\circ} n

tan^{2} (θ) - tan (θ) = 0, θ, 0 \leq θ < 2 π

cos (4 x) - 4 cos (2 x) = 5

sin (x) = sin (x + (- 3) π)

sin (2 x) - \frac{2}{3} = 0

2 sin (θ) + cos (2 θ) = 0

What is the general solution for cos(A-25)+cos(A+25)=cos(25) ?
The general solution for cos(A-25)+cos(A+25)=cos(25) is A=60+360n,A=300+360n