What is the general solution for sin(x)=-(sqrt(2))/2 ,-pi<= x<= pi ?

The general solution for sin(x)=-(sqrt(2))/2 ,-pi<= x<= pi is x=-(3pi)/4 ,x=-pi/4

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sin(x)=-(sqrt(2))/2 ,-pi<= x<= pi

sin (x) = - \frac{2}{2}, - π \leq x \leq π

x = - \frac{3 π}{4}, x = - \frac{π}{4}

Solution steps

sin (x) = - \frac{2}{2}, - π \leq x \leq π

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solutions for the range

- π \leq x \leq π

x = - \frac{3 π}{4}, x = - \frac{π}{4}

w, s (t) = A e^{- c t} cos (wt + b)

0 = 2 sin (t) + cos (2 t)

8 cos (θ) = - 4

2 sin (3 x + π) = - 1

t, f = cos (a t)

What is the general solution for sin(x)=-(sqrt(2))/2 ,-pi<= x<= pi ?
The general solution for sin(x)=-(sqrt(2))/2 ,-pi<= x<= pi is x=-(3pi)/4 ,x=-pi/4