What is the general solution for 8cos(θ)=-4 ?

The general solution for 8cos(θ)=-4 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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8cos(θ)=-4

8 cos (θ) = - 4

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

8 cos (θ) = - 4

Divide both sides by

8

cos (θ) = - \frac{1}{2}

General solutions for

cos (θ) = - \frac{1}{2}

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

2 sin (3 x + π) = - 1

t, f = cos (a t)

2 cos (x) + 1 = 0, π < x < 4 π

cos (3 x) = 3

4 cos^{2} (θ) - 5 cos (θ) = - 4 cos (θ) + 3

What is the general solution for 8cos(θ)=-4 ?
The general solution for 8cos(θ)=-4 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin