What is the general solution for solvefor t,f=cos(at) ?

The general solution for solvefor t,f=cos(at) is t=(arccos(f))/a+(2pin)/a ,t=-(arccos(f))/a+(2pin)/a

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solvefor t,f=cos(at)

solve for

t, f = cos (a t)

t = \frac{arccos ( f )}{a} + \frac{2 πn}{a}, t = - \frac{arccos ( f )}{a} + \frac{2 πn}{a}

Solution steps

f = cos (a t)

Switch sides

cos (a t) = f

Apply trig inverse properties

a t = arccos (f) + 2 πn, a t = - arccos (f) + 2 πn

Solve

a t = arccos (f) + 2 πn : t = \frac{arccos ( f )}{a} + \frac{2 πn}{a}; a \neq = 0

Solve

a t = - arccos (f) + 2 πn : t = - \frac{arccos ( f )}{a} + \frac{2 πn}{a}; a \neq = 0

t = \frac{arccos ( f )}{a} + \frac{2 πn}{a}, t = - \frac{arccos ( f )}{a} + \frac{2 πn}{a}

2 cos (x) + 1 = 0, π < x < 4 π

cos (3 x) = 3

4 cos^{2} (θ) - 5 cos (θ) = - 4 cos (θ) + 3

x, cos (x) = - 0.5

- 2 cos (x) = 3 sin (x)

What is the general solution for solvefor t,f=cos(at) ?
The general solution for solvefor t,f=cos(at) is t=(arccos(f))/a+(2pin)/a ,t=-(arccos(f))/a+(2pin)/a