What is the general solution for sqrt(2)cos(x)+1=0,pi<x<4pi ?

The general solution for sqrt(2)cos(x)+1=0,pi<x<4pi is x=(5pi)/4 ,x=(11pi)/4 ,x=(13pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(2)cos(x)+1=0,pi<x<4pi

2 cos (x) + 1 = 0, π < x < 4 π

x = \frac{5 π}{4}, x = \frac{11 π}{4}, x = \frac{13 π}{4}

Solution steps

2 cos (x) + 1 = 0, π < x < 4 π

Move

1

to the right side

2 cos (x) = - 1

Divide both sides by

2

cos (x) = - \frac{2}{2}

General solutions for

cos (x) = - \frac{2}{2}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

Solutions for the range

π < x < 4 π

x = \frac{5 π}{4}, x = \frac{11 π}{4}, x = \frac{13 π}{4}

cos (3 x) = 3

4 cos^{2} (θ) - 5 cos (θ) = - 4 cos (θ) + 3

x, cos (x) = - 0.5

- 2 cos (x) = 3 sin (x)

3 sin (x) - cos (2 x) = 1

What is the general solution for sqrt(2)cos(x)+1=0,pi<x<4pi ?
The general solution for sqrt(2)cos(x)+1=0,pi<x<4pi is x=(5pi)/4 ,x=(11pi)/4 ,x=(13pi)/4