What is the general solution for 10cos(2x)-3=2 ?

The general solution for 10cos(2x)-3=2 is x= pi/6+pin,x=(5pi)/6+pin

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10cos(2x)-3=2

10 cos (2 x) - 3 = 2

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

10 cos (2 x) - 3 = 2

Move

3

to the right side

10 cos (2 x) = 5

Divide both sides by

10

cos (2 x) = \frac{1}{2}

General solutions for

cos (2 x) = \frac{1}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

sin^{2} (θ) = 9 (cos (- θ) + 1)

sin (30 x) = 202.07

sin (x) - cos^{2} (x) = 0

x, sin (x^{2}) + cos (y^{3}) = - 2

8 sin (12 0^{\circ} - x) = 9 sin (x)

What is the general solution for 10cos(2x)-3=2 ?
The general solution for 10cos(2x)-3=2 is x= pi/6+pin,x=(5pi)/6+pin