What is the general solution for sin^2(θ)=9(cos(-θ)+1) ?

The general solution for sin^2(θ)=9(cos(-θ)+1) is θ=pi+2pin

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sin^2(θ)=9(cos(-θ)+1)

sin^{2} (θ) = 9 (cos (- θ) + 1)

θ = π + 2 πn

Solution steps

sin^{2} (θ) = 9 (cos (- θ) + 1)

Rewrite using trig identities

sin^{2} (θ) = 9 (1 + cos (θ))

Subtract

9 (1 + cos (θ))

from both sides

sin^{2} (θ) - 9 (1 + cos (θ)) = 0

Rewrite using trig identities

- 8 - cos^{2} (θ) - 9 cos (θ) = 0

Solve by substitution

cos (θ) = - 8, cos (θ) = - 1

cos (θ) = - 8 :

No Solution

cos (θ) = - 1 : θ = π + 2 πn

Combine all the solutions

θ = π + 2 πn

sin (30 x) = 202.07

sin (x) - cos^{2} (x) = 0

x, sin (x^{2}) + cos (y^{3}) = - 2

8 sin (12 0^{\circ} - x) = 9 sin (x)

cos (θ) = 0.625

What is the general solution for sin^2(θ)=9(cos(-θ)+1) ?
The general solution for sin^2(θ)=9(cos(-θ)+1) is θ=pi+2pin