What is the general solution for 1-sin(t)=0 ?

The general solution for 1-sin(t)=0 is t= pi/2+2pin

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1-sin(t)=0

1 - sin (t) = 0

t = \frac{π}{2} + 2 πn

Solution steps

1 - sin (t) = 0

Move

1

to the right side

- sin (t) = - 1

Divide both sides by

- 1

sin (t) = 1

General solutions for

sin (t) = 1

t = \frac{π}{2} + 2 πn

θ, 6 = ρ sin (φ) sin (θ)

tan^{2} (θ) sec^{2} (θ) = 3

2 cos (θ) = cos (θ)

sin^{2} (x) \cdot cos (x) + 1 = 0

sin (B) = \frac{1}{2}, a = 170

What is the general solution for 1-sin(t)=0 ?
The general solution for 1-sin(t)=0 is t= pi/2+2pin