What is the general solution for 2cos(θ)=cos(θ) ?

The general solution for 2cos(θ)=cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin

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2cos(θ)=cos(θ)

2 cos (θ) = cos (θ)

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

2 cos (θ) = cos (θ)

Solve by substitution

cos (θ) = 0

cos (θ) = 0 : θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

sin^{2} (x) \cdot cos (x) + 1 = 0

sin (B) = \frac{1}{2}, a = 170

sin (x - \frac{5 π}{3}) + sin (x + \frac{5 π}{3}) = 1

- sec (\frac{x}{2}) = 2 csc (\frac{x}{2})

sec^{2} (θ) - sec (θ) = 2, θ [0, \frac{π}{2}]

What is the general solution for 2cos(θ)=cos(θ) ?
The general solution for 2cos(θ)=cos(θ) is θ= pi/2+2pin,θ=(3pi)/2+2pin