{
"query": {
"display": "solve for $$a,\\:P=\\cot^{2}\\left(a\\right)$$",
"symbolab_question": "SOLVE_FOR#solvefor a,P=\\cot^{2}(a)"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "a=\\arccot(\\sqrt{P})+πn,a=\\arccot(-\\sqrt{P})+πn",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$solve\\:for\\:a,\\:P=\\cot^{2}\\left(a\\right){\\quad:\\quad}a=\\arccot\\left(\\sqrt{P}\\right)+πn,\\:a=\\arccot\\left(-\\sqrt{P}\\right)+πn$$",
"input": "P=\\cot^{2}\\left(a\\right)",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "\\cot^{2}\\left(a\\right)=P"
},
{
"type": "interim",
"title": "Solve by substitution",
"input": "\\cot^{2}\\left(a\\right)=P",
"result": "\\cot\\left(a\\right)=\\sqrt{P},\\:\\cot\\left(a\\right)=-\\sqrt{P}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cot\\left(a\\right)=u$$",
"result": "u^{2}=P"
},
{
"type": "interim",
"title": "$$u^{2}=P{\\quad:\\quad}u=\\sqrt{P},\\:u=-\\sqrt{P}$$",
"input": "u^{2}=P",
"steps": [
{
"type": "step",
"primary": "For $$x^{2}=f\\left(a\\right)$$ the solutions are $$x=\\sqrt{f\\left(a\\right)},\\:\\:-\\sqrt{f\\left(a\\right)}$$"
},
{
"type": "step",
"result": "u=\\sqrt{P},\\:u=-\\sqrt{P}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cot\\left(a\\right)$$",
"result": "\\cot\\left(a\\right)=\\sqrt{P},\\:\\cot\\left(a\\right)=-\\sqrt{P}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cot\\left(a\\right)=\\sqrt{P}{\\quad:\\quad}a=\\arccot\\left(\\sqrt{P}\\right)+πn$$",
"input": "\\cot\\left(a\\right)=\\sqrt{P}",
"steps": [
{
"type": "interim",
"title": "Apply trig inverse properties",
"input": "\\cot\\left(a\\right)=\\sqrt{P}",
"result": "a=\\arccot\\left(\\sqrt{P}\\right)+πn",
"steps": [
{
"type": "step",
"primary": "General solutions for $$\\cot\\left(a\\right)=\\sqrt{P}$$",
"secondary": [
"$$\\cot\\left(x\\right)=a\\quad\\Rightarrow\\quad\\:x=\\arccot\\left(a\\right)+πn$$"
],
"result": "a=\\arccot\\left(\\sqrt{P}\\right)+πn"
}
],
"meta": {
"interimType": "Trig Apply Inverse Props 0Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cot\\left(a\\right)=-\\sqrt{P}{\\quad:\\quad}a=\\arccot\\left(-\\sqrt{P}\\right)+πn$$",
"input": "\\cot\\left(a\\right)=-\\sqrt{P}",
"steps": [
{
"type": "interim",
"title": "Apply trig inverse properties",
"input": "\\cot\\left(a\\right)=-\\sqrt{P}",
"result": "a=\\arccot\\left(-\\sqrt{P}\\right)+πn",
"steps": [
{
"type": "step",
"primary": "General solutions for $$\\cot\\left(a\\right)=-\\sqrt{P}$$",
"secondary": [
"$$\\cot\\left(x\\right)=a\\quad\\Rightarrow\\quad\\:x=\\arccot\\left(a\\right)+πn$$"
],
"result": "a=\\arccot\\left(-\\sqrt{P}\\right)+πn"
}
],
"meta": {
"interimType": "Trig Apply Inverse Props 0Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "a=\\arccot\\left(\\sqrt{P}\\right)+πn,\\:a=\\arccot\\left(-\\sqrt{P}\\right)+πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "a",
"plotRequest": "P-\\cot^{2}(a)"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
solve for
Solution
Solution steps
Switch sides
Solve by substitution
Let:
For the solutions are
Substitute back
Apply trig inverse properties
General solutions for
Apply trig inverse properties
General solutions for
Combine all the solutions
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the general solution for solvefor a,P=cot^2(a) ?
The general solution for solvefor a,P=cot^2(a) is a=arccot(sqrt(P))+pin,a=arccot(-sqrt(P))+pin