What is the general solution for tan(θ)=(3/1-2/5)/(1+3/1*2/5) ?

The general solution for tan(θ)=(3/1-2/5)/(1+3/1*2/5) is θ=0.86853…+pin

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tan(θ)=(3/1-2/5)/(1+3/1*2/5)

tan (θ) = \frac{\frac{3}{1} - \frac{2}{5}}{1 + \frac{3}{1} \cdot \frac{2}{5}}

θ = 0.86853 \dots + πn

Solution steps

tan (θ) = \frac{\frac{3}{1} - \frac{2}{5}}{1 + \frac{3}{1} \cdot \frac{2}{5}}

Simplify

\frac{\frac{3}{1} - \frac{2}{5}}{1 + \frac{3}{1} \cdot \frac{2}{5}} : \frac{13}{11}

Apply trig inverse properties

θ = arctan (\frac{13}{11}) + πn

Show solutions in decimal form

θ = 0.86853 \dots + πn

tan (t) = 14

cos (A) = \frac{5}{8}

sin (9 x + 40) = cos (- 5 x + 42)

sin^{2} (a) = - \frac{( 5 11 )}{( 18 )}

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) + 11.7 = 14

What is the general solution for tan(θ)=(3/1-2/5)/(1+3/1*2/5) ?
The general solution for tan(θ)=(3/1-2/5)/(1+3/1*2/5) is θ=0.86853…+pin