What is the general solution for 2sin(5x)=1 ?

The general solution for 2sin(5x)=1 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5

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2sin(5x)=1

2 sin (5 x) = 1

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

Solution steps

2 sin (5 x) = 1

Divide both sides by

2

sin (5 x) = \frac{1}{2}

General solutions for

sin (5 x) = \frac{1}{2}

5 x = \frac{π}{6} + 2 πn, 5 x = \frac{5 π}{6} + 2 πn

Solve

5 x = \frac{π}{6} + 2 πn : x = \frac{π}{30} + \frac{2 πn}{5}

Solve

5 x = \frac{5 π}{6} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{5}

x = \frac{π}{30} + \frac{2 πn}{5}, x = \frac{π}{6} + \frac{2 πn}{5}

cos (2 x) = - \frac{17}{81}

sin^{2} (θ) + cos (2 θ) = 0

csc (θ) = \frac{28}{2}, sin (θ)

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

sin (θ) = \frac{2}{6}

What is the general solution for 2sin(5x)=1 ?
The general solution for 2sin(5x)=1 is x= pi/(30)+(2pin)/5 ,x= pi/6+(2pin)/5