What is the general solution for sin^2(θ)+cos(2θ)=0 ?

The general solution for sin^2(θ)+cos(2θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

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sin^2(θ)+cos(2θ)=0

sin^{2} (θ) + cos (2 θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (θ) + cos (2 θ) = 0

Rewrite using trig identities

cos^{2} (θ) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

csc (θ) = \frac{28}{2}, sin (θ)

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

sin (θ) = \frac{2}{6}

3 sin (2 x) = - 2

x, arctan (y) = 2 arctan (x)

What is the general solution for sin^2(θ)+cos(2θ)=0 ?
The general solution for sin^2(θ)+cos(2θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin