What is the general solution for cos(θ)=sec(θ),0<= θ<2pi ?

The general solution for cos(θ)=sec(θ),0<= θ<2pi is θ=0,θ=pi

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cos(θ)=sec(θ),0<= θ<2pi

cos (θ) = sec (θ), 0 \leq θ < 2 π

θ = 0, θ = π

Solution steps

cos (θ) = sec (θ), 0 \leq θ < 2 π

Subtract

sec (θ)

from both sides

cos (θ) - sec (θ) = 0

Rewrite using trig identities

\frac{1}{sec ( θ )} - sec (θ) = 0

Solve by substitution

sec (θ) = 1, sec (θ) = - 1

sec (θ) = 1, 0 \leq θ < 2 π : θ = 0

sec (θ) = - 1, 0 \leq θ < 2 π : θ = π

Combine all the solutions

θ = 0, θ = π

\frac{441}{841} + sin^{2} (t) = 1

3 cot (\frac{2 x}{3}) - 1 = 0

2 sin (3 x) = 1, 0 \leq x \leq 4 π

\frac{4}{cos ( x )} - 6 = tan (x)

tan (2 a) cot (a + 2 0^{\circ}) = 1

What is the general solution for cos(θ)=sec(θ),0<= θ<2pi ?
The general solution for cos(θ)=sec(θ),0<= θ<2pi is θ=0,θ=pi