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Popular Trigonometry >

15=25+2*sqrt(100)*cos(x)

  • Pre Algebra
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Solution

15=25+2⋅100​⋅cos(x)

Solution

x=32π​+2πn,x=34π​+2πn
+1
Degrees
x=120∘+360∘n,x=240∘+360∘n
Solution steps
15=25+2100​cos(x)
Switch sides25+2100​cos(x)=15
2100​cos(x)=20cos(x)
2100​cos(x)
100​=10
100​
Factor the number: 100=102=102​
Apply radical rule: 102​=10=10
=2⋅10cos(x)
Multiply the numbers: 2⋅10=20=20cos(x)
25+20cos(x)=15
Move 25to the right side
25+20cos(x)=15
Subtract 25 from both sides25+20cos(x)−25=15−25
Simplify20cos(x)=−10
20cos(x)=−10
Divide both sides by 20
20cos(x)=−10
Divide both sides by 202020cos(x)​=20−10​
Simplify
2020cos(x)​=20−10​
Simplify 2020cos(x)​:cos(x)
2020cos(x)​
Divide the numbers: 2020​=1=cos(x)
Simplify 20−10​:−21​
20−10​
Apply the fraction rule: b−a​=−ba​=−2010​
Cancel the common factor: 10=−21​
cos(x)=−21​
cos(x)=−21​
cos(x)=−21​
General solutions for cos(x)=−21​
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
x=32π​+2πn,x=34π​+2πn
x=32π​+2πn,x=34π​+2πn

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Popular Examples

-4sqrt(3)=12tan(θ)tan(2θ)=2.43sin^2(θ)=2sin(θ)+3(sin(180)}{20}=\frac{sin(a))/8(sin(x)+cos(x))^2=1^2

Frequently Asked Questions (FAQ)

  • What is the general solution for 15=25+2*sqrt(100)*cos(x) ?

    The general solution for 15=25+2*sqrt(100)*cos(x) is x=(2pi)/3+2pin,x=(4pi)/3+2pin
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