What is the general solution for (sin(180)}{20}=\frac{sin(a))/8 ?

The general solution for (sin(180)}{20}=\frac{sin(a))/8 is a=360n,a=180+360n

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(sin(180)}{20}=\frac{sin(a))/8

\frac{sin ( 18 0 ^{\circ} )}{20} = \frac{sin ( a )}{8}

a = 36 0^{\circ} n, a = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

\frac{sin ( 18 0 ^{\circ} )}{20} = \frac{sin ( a )}{8}

sin (18 0^{\circ}) = 0

\frac{0}{20} = \frac{sin ( a )}{8}

Switch sides

\frac{sin ( a )}{8} = \frac{0}{20}

Multiply both sides by

10

\frac{5 sin ( a )}{4} = 0

Multiply both sides by

4

5 sin (a) = 0

Divide both sides by

5

sin (a) = 0

General solutions for

sin (a) = 0

a = 0 + 36 0^{\circ} n, a = 18 0^{\circ} + 36 0^{\circ} n

Solve

a = 0 + 36 0^{\circ} n : a = 36 0^{\circ} n

a = 36 0^{\circ} n, a = 18 0^{\circ} + 36 0^{\circ} n

(sin (x) + cos (x))^{2} = 1^{2}

tan (4 x) = 12

4 csc (B) + 5 = 0

2 cos (\frac{π}{5} x) = 3

sin^{2} (x) + 8 sin (x) - 1 = 0

What is the general solution for (sin(180)}{20}=\frac{sin(a))/8 ?
The general solution for (sin(180)}{20}=\frac{sin(a))/8 is a=360n,a=180+360n