What is the general solution for 4csc(B)+5=0 ?

The general solution for 4csc(B)+5=0 is B=-0.92729…+2pin,B=pi+0.92729…+2pin

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4csc(B)+5=0

4 csc (B) + 5 = 0

B = - 0.92729 \dots + 2 πn, B = π + 0.92729 \dots + 2 πn

Solution steps

4 csc (B) + 5 = 0

Move

5

to the right side

4 csc (B) = - 5

Divide both sides by

4

csc (B) = - \frac{5}{4}

Apply trig inverse properties

B = arccsc (- \frac{5}{4}) + 2 πn, B = π + arccsc (\frac{5}{4}) + 2 πn

Show solutions in decimal form

B = - 0.92729 \dots + 2 πn, B = π + 0.92729 \dots + 2 πn

2 cos (\frac{π}{5} x) = 3

sin^{2} (x) + 8 sin (x) - 1 = 0

x, y = arctan (2 x + 3 y)

sin (2 x) = 0.89583

tan (θ) = 1.234, θ

What is the general solution for 4csc(B)+5=0 ?
The general solution for 4csc(B)+5=0 is B=-0.92729…+2pin,B=pi+0.92729…+2pin