What is the general solution for -4sqrt(3)=12tan(θ) ?

The general solution for -4sqrt(3)=12tan(θ) is θ=(5pi)/6+pin

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-4sqrt(3)=12tan(θ)

- 43 = 12 tan (θ)

θ = \frac{5 π}{6} + πn

Solution steps

- 43 = 12 tan (θ)

Switch sides

12 tan (θ) = - 43

Divide both sides by

12

tan (θ) = - \frac{3}{3}

General solutions for

tan (θ) = - \frac{3}{3}

θ = \frac{5 π}{6} + πn

tan (2 θ) = 2.4

3 sin^{2} (θ) = 2 sin (θ) + 3

\frac{sin ( 18 0 ^{\circ} )}{20} = \frac{sin ( a )}{8}

(sin (x) + cos (x))^{2} = 1^{2}

tan (4 x) = 12

What is the general solution for -4sqrt(3)=12tan(θ) ?
The general solution for -4sqrt(3)=12tan(θ) is θ=(5pi)/6+pin