What is the general solution for -2cos(θ)=0 ?

The general solution for -2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2cos(θ)=0

- 2 cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Solution steps

- 2 cos (θ) = 0

Divide both sides by

- 2

cos (θ) = 0

General solutions for

cos (θ) = 0

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

2 cos^{2} (x) + 15 sin (x) = 9

cot (θ) = 1.413

arccos (x) + arccos (2 x) = arccos (\frac{1}{2})

tan (θ) = \frac{2 3}{3} sin (θ), 0 \leq θ \leq 2 π

x, cos (x + y) = - cos (x)

What is the general solution for -2cos(θ)=0 ?
The general solution for -2cos(θ)=0 is θ= pi/2+2pin,θ=(3pi)/2+2pin