What is the general solution for 2cos^2(θ)-7cos(θ)+3=0,θ ?

The general solution for 2cos^2(θ)-7cos(θ)+3=0,θ is No Solution for θ\in\mathbb{R}

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2cos^2(θ)-7cos(θ)+3=0,θ

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0, θ

No Solution for θ \in R

Solution steps

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0, θ

Solve by substitution

cos (θ) = 3, cos (θ) = \frac{1}{2}

cos (θ) = 3, θ :

No Solution

cos (θ) = \frac{1}{2}, θ :

No Solution

Combine all the solutions

No Solution for θ \in R

2 (sin^{2} (x)) + 5 sin (x) - 3 = 0

cos^{2} (3 x) - sin^{2} (3 x) = - 1

x, arctan (\frac{y}{x}) = \frac{π}{4}

(1 + cos (x)) (tan (x) - 1) = 0

cos (x) = \pm \frac{1}{2}

What is the general solution for 2cos^2(θ)-7cos(θ)+3=0,θ ?
The general solution for 2cos^2(θ)-7cos(θ)+3=0,θ is No Solution for θ\in\mathbb{R}