What is the general solution for 25=-20cos((2pi)/(365)(x+10))+25 ?

The general solution for 25=-20cos((2pi)/(365)(x+10))+25 is x=365n+325/4 ,x=365n+1055/4

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25=-20cos((2pi)/(365)(x+10))+25

25 = - 20 cos (\frac{2 π}{365} (x + 10)) + 25

x = 365 n + \frac{325}{4}, x = 365 n + \frac{1055}{4}

Solution steps

25 = - 20 cos (\frac{2 π}{365} (x + 10)) + 25

Switch sides

- 20 cos (\frac{2 π}{365} (x + 10)) + 25 = 25

Subtract

25

from both sides

- 20 cos (\frac{2 π}{365} (x + 10)) + 25 - 25 = 25 - 25

Simplify

- 20 cos (\frac{2 π}{365} (x + 10)) = 0

Divide both sides by

- 20

cos (\frac{2 π}{365} (x + 10)) = 0

General solutions for

cos (\frac{2 π}{365} (x + 10)) = 0

\frac{2 π}{365} (x + 10) = \frac{π}{2} + 2 πn, \frac{2 π}{365} (x + 10) = \frac{3 π}{2} + 2 πn

Solve

\frac{2 π}{365} (x + 10) = \frac{π}{2} + 2 πn : x = 365 n + \frac{325}{4}

Solve

\frac{2 π}{365} (x + 10) = \frac{3 π}{2} + 2 πn : x = 365 n + \frac{1055}{4}

x = 365 n + \frac{325}{4}, x = 365 n + \frac{1055}{4}

sin (x) - cos (x) - \frac{1}{2} = 0

cos^{2} (θ) = \frac{49}{64}

sec^{2} (θ) = 1 - tan (θ)

cos^{2} (x) = - 0.267

sin (x - 4) = cos (9 x + 4)

What is the general solution for 25=-20cos((2pi)/(365)(x+10))+25 ?
The general solution for 25=-20cos((2pi)/(365)(x+10))+25 is x=365n+325/4 ,x=365n+1055/4