What is the general solution for 4=4cos(x) ?

The general solution for 4=4cos(x) is x=2pin

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4=4cos(x)

4 = 4 cos (x)

x = 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n

Solution steps

4 = 4 cos (x)

Switch sides

4 cos (x) = 4

Divide both sides by

4

4 cos (x) = 4

Divide both sides by

4

\frac{4 cos ( x )}{4} = \frac{4}{4}

Simplify

cos (x) = 1

cos (x) = 1

General solutions for

cos (x) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

cos^{2} (x) = 2 sin (x) - 2

- 3 = 39.6862600000000 \dots cos (x)

1 + cos (θ) = - cos (θ)

2 cos^{2} (x) - cos (- x) - 1 = 0

3 sec^{2} (u) + 7 tan (u) = 3

What is the general solution for 4=4cos(x) ?
The general solution for 4=4cos(x) is x=2pin